Constructing+the+name+of+an+Ionic+Compound


 * Constructing the name of an Ionic Compound ** (p71-72)

What is an Ionic Compound ?
 * An **IONIC COMPOUND** is a compound made up of ** ions **.
 * It contains a **metal** ion and a **non-metal ion**

Steps: 1. Determine the name of the  **metal ion** . 2. Determine if the metal ion has **more than one** possible charge. 3. Determine the name of the **non-metal ion (don't forget to change the end of the name to 'ide')** . 4. *Remove the words "ion" 5.*If the metal ion has more than one possible charge, just write the same  **Roman number** of the charge after the name of metal ion.  6.Put the name of the metal ion and the non-metal ion toghther <span style="font-family: 'Comic Sans MS',cursive; font-size: 130%;">. ( write the name of metal ion first ) <span style="font-family: 'Comic Sans MS',cursive; font-size: 130%;">E.g. <span style="color: #5757d1; font-family: 'Comic Sans MS',cursive; font-size: 130%;">NaCl <span style="font-family: 'Comic Sans MS',cursive; font-size: 130%;">1. Name the metal ion (Na+) : <span style="color: #d54d77; font-family: 'Comic Sans MS',cursive; font-size: 130%;">Sodium ion <span style="font-family: 'Comic Sans MS',cursive; font-size: 140%;">2. Na only has one possible charge, so go to step 3 3. Name the non-metal ion (Cl-) : Chloride ion 4. Remove the word " ion " 5. Put them together : Sodium Chloride
 * Naming Ionic Compound **

<span style="color: #5757d1; font-family: 'Comic Sans MS',cursive; font-size: 140%;">CuCl2 <span style="color: #49b738; font-family: 'Comic Sans MS',cursive; font-size: 140%;">un-criss-crossing the subscripts gives (Cu 2+ ** ) ** 1 ( <span style="color: #49b738; font-family: 'Comic Sans MS',cursive; font-size: 140%;">Cl - ) 2 <span style="color: #d54d77; font-family: 'Comic Sans MS',cursive; font-size: 140%;"> 1. Name the metal ion ( Cu? ) : Copper ion <span style="font-family: 'Comic Sans MS',cursive; font-size: 140%;">2. Copper ion has more than one possible charge, it can be <span style="color: #008080; font-family: 'Comic Sans MS',cursive; font-size: 140%;"> Cu+ <span style="font-family: 'Comic Sans MS',cursive; font-size: 140%;"> or <span style="color: #008080; font-family: 'Comic Sans MS',cursive; font-size: 140%;">Cu <span style="color: #008080; font-family: 'Comic Sans MS',cursive; font-size: 140%; vertical-align: super;">2+ <span style="font-family: 'Comic Sans MS',cursive; font-size: 140%;"> and from this formula we can know that the charge of Cu in this case should be <span style="color: #ff00ff; font-family: 'Comic Sans MS',cursive; font-size: 140%;">+2 <span style="font-family: 'Comic Sans MS',cursive; font-size: 140%;">3. Name the non-metal ion ( Cl- ) : <span style="color: #d54d77; font-family: 'Comic Sans MS',cursive; font-size: 140%;">Chloride ion <span style="font-family: 'Comic Sans MS',cursive; font-size: 140%;"> 4. Remove the word " ion" 5. Add same Roman number of the charge after the name of metal ion : <span style="color: #d54d77; font-family: 'Comic Sans MS',cursive; font-size: 140%;">Copper (II) <span style="color: #000000; font-family: 'Comic Sans MS',cursive; font-size: 140%;">6. Put the names together : <span style="color: #c9406a; font-family: 'Comic Sans MS',cursive; font-size: 140%;">Copper (II) Chloride